No, the acceleration of a ball on a constant inclined plane is not always constant at 981 m/s². The acceleration of a ball on an inclined plane is determined by the angle of the incline and the force of gravity acting on the ball. The acceleration can be calculated using the formula a = g sin(θ), where g is the acceleration due to gravity (approximately 9.81 m/s²) and θ is the angle of the incline. Therefore, the acceleration of a ball on a constant inclined plane will vary depending on the angle of the incline. **

To reflect a plane on the plane x1x3, you would first find the equation of the plane you want to reflect. Then, you would substitute x2 with -x2 in the equation to reflect it across the x1x3 plane. This means changing the sign of the coefficient of x2 in the equation of the plane. The resulting equation will be the reflection of the original plane across the x1x3 plane. **

To reflect a plane across the plane x1x3, you can first find the equation of the mirror plane x1x3. Then, for each point on the original plane, you can find its reflection across the mirror plane by using the formula for reflecting a point across a plane. This involves finding the perpendicular distance from the point to the mirror plane and then using that distance to find the reflected point. By applying this process to all points on the original plane, you can obtain the reflected plane across the x1x3 plane. **

There are several reasons why a home network might have a 100 Mbit/s connection instead of a 1 Gbit/s connection. One reason could be cost, as 100 Mbit/s equipment is often less expensive than 1 Gbit/s equipment. Another reason could be that the devices on the network may not require the higher speed, such as older computers or devices that do not support gigabit speeds. Additionally, the infrastructure of the home network, such as the cabling and networking hardware, may not be capable of supporting gigabit speeds. **

To determine a parallel plane to a given plane, you can use the normal vector of the given plane. If the normal vector of the given plane is (a, b, c), then the parallel plane will have the same normal vector. You can then use this normal vector to find the equation of the parallel plane. If the given plane has the equation Ax + By + Cz + D = 0, then the parallel plane will have the equation Ax + By + Cz + K = 0, where K is a constant. This will ensure that the two planes are parallel to each other. **

To establish a parallel plane to the x1-x2 plane, one can use the equation of the x1-x2 plane, which is typically written as z = 0. To create a parallel plane, one can simply add or subtract a constant value from the right-hand side of the equation. For example, to create a parallel plane that is 3 units above the x1-x2 plane, the equation would be z = 3. This will create a new plane that is parallel to the x1-x2 plane and shifted vertically by 3 units. **

The support vector of another plane in the same plane is the vector that is perpendicular to the plane. In other words, it is a vector that is orthogonal to the plane and lies entirely within the plane. This vector is important in defining the orientation and position of the plane in space. **

To establish a plane parallel to the x1-x2 plane, one can choose any point not on the x1-x2 plane. Then, draw a line perpendicular to the x1-x2 plane from that point. This line will intersect the x1-x2 plane at a single point. Finally, construct a plane that is parallel to the x1-x2 plane and passes through the point where the perpendicular line intersects the x1-x2 plane. **